1. Runtime Distribution
2. Submission Details
3. Description
Given a sorted positive integer array nums and an integer n, add/patch elements to the array such that any number in range [1, n] inclusive can be formed by the sum of some elements in the array. Return the minimum number of patches required.
4. Example
Example 1:
nums = [1, 3], n = 6
Return 1.
Combinations of nums are [1], [3], [1,3], which form possible sums of: 1, 3, 4.
Now if we add/patch 2 to nums, the combinations are: [1], [2], [3], [1,3], [2,3], [1,2,3].
Possible sums are 1, 2, 3, 4, 5, 6, which now covers the range [1, 6].
So we only need 1 patch.
Example 2:
nums = [1, 5, 10], n = 20
Return 2.
The two patches can be [2, 4].
Example 3:
nums = [1, 2, 2], n = 5
Return 0.
5. Code
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public int minPatches(int[] nums, int n) { int patch = 0; long max = 1; for(int i = 0, needPatch = 0; i < nums.length && max <= n; i += needPatch ^ 1){ needPatch = nums[i] <= max ? 0 : 1; max += needPatch == 0 ? nums[i] : max; patch += needPatch; } for(;max <= n;max += max, patch ++); return patch; }
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6.Test
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import org.junit.Test; public class LeetCode0330 { public int minPatches(int[] nums, int n) { int patch = 0; long max = 1; for(int i = 0, needPatch = 0; i < nums.length && max <= n; i += needPatch ^ 1){ needPatch = nums[i] <= max ? 0 : 1; max += needPatch == 0 ? nums[i] : max; patch += needPatch; } for(;max <= n;max += max, patch ++); return patch; } @Test public void test(){ int[] nums = {1,2,31,33}; System.out.println(minPatches(nums, 2147483647)); } }
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